RESOLUTION OF THE EQUATION (3(x1)-1)(3(x2)-1) = (5(y1)-1)(5(y2)-1)

Liptai K., Nemeth L., SOYDAN G., Szalay L.

ROCKY MOUNTAIN JOURNAL OF MATHEMATICS, cilt.50, sa.4, ss.1425-1433, 2020 (SCI-Expanded) identifier identifier identifier

  • Yayın Türü: Makale / Tam Makale
  • Cilt numarası: 50 Sayı: 4
  • Basım Tarihi: 2020
  • Doi Numarası: 10.1216/rmj.2020.50.1425
  • Dergi Adı: ROCKY MOUNTAIN JOURNAL OF MATHEMATICS
  • Derginin Tarandığı İndeksler: Science Citation Index Expanded (SCI-EXPANDED), Scopus, MathSciNet, zbMATH, DIALNET
  • Sayfa Sayıları: ss.1425-1433
  • Bursa Uludağ Üniversitesi Adresli: Evet

Özet

Consider the diophantine equation (3(x1) - 1)(3(x2) - 1) = (5(y1) - 1)(5(y2) - 1) in positive integers x(1) <= x(2) and y(1) <= y(2). Each side of the equation is a product of two terms of a given binary recurrence. We prove that the only solution to the title equation is (x(1), x(2), y(1), y(2)) = (1, 2, 1, 1). The main novelty of our result is that we allow products of two terms on both sides.